sd-binary {scrutiny} | R Documentation |
Standard deviation of binary data
Description
Compute the sample SD of binary data (i.e., only 0 and 1 values) in either of four ways, each based on different inputs:
-
sd_binary_groups()
takes the cell sizes of both groups, those coded as 0 and those coded as 1. -
sd_binary_0_n()
takes the cell size of the group coded as 0 and the total sample size. -
sd_binary_1_n()
takes the cell size of the group coded as 1 and the total sample size. -
sd_binary_mean_n()
takes the mean and the total sample size.
These functions are used as helpers inside debit()
, and consequently
debit_map()
.
Usage
sd_binary_groups(group_0, group_1)
sd_binary_0_n(group_0, n)
sd_binary_1_n(group_1, n)
sd_binary_mean_n(mean, n)
Arguments
group_0 |
Integer. Cell size of the group coded as 0. |
group_1 |
Integer. Cell size of the group coded as 1. |
n |
Integer. Total sample size. |
mean |
Numeric. Mean of the binary data. |
Value
Numeric. Sample standard deviation.
References
Heathers, James A. J., and Brown, Nicholas J. L. 2019. DEBIT: A Simple Consistency Test For Binary Data. https://osf.io/5vb3u/.
See Also
is_subset_of_vals(x, 0, 1)
checks whether x
(a list or atomic
vector) contains nothing but binary numbers.
Examples
# If 127 values are coded as 0 and 153 as 1...
sd_binary_groups(group_0 = 127, group_1 = 153)
# ...so that n = 280:
sd_binary_0_n(group_0 = 127, n = 280)
sd_binary_1_n(group_1 = 153, n = 280)
# If only the mean and total sample size are
# given, or these are more convenient to use,
# they still lead to the same result as above
# if the mean is given with a sufficiently
# large number of decimal places:
sd_binary_mean_n(mean = 0.5464286, n = 280)