zapspace {kutils} | R Documentation |
Convert leading or trailing white space and tab characters to nothing.
Description
This eliminates any characters matched by the regular expression
'\s' if they appear at the beginning of a string or at its
end. It does not alter spaces in the interior of a string. This
was created when I was not aware of R's trimws
and the purpose
is the same. On our TODO list, we intend to eliminate this function
and replace its use with trimws
Usage
zapspace(x)
Arguments
x |
A character vector |
Value
If x is a character vector, return is a character vector with leading and trailing white space values removed. If x is not a character vector, an unaltered x is returned.
Author(s)
Paul Johnson <pauljohn@ku.edu>
Examples
x <- c("", " ", " ", "\t", "\t some", "some\t", " space first")
zapspace(x)
[Package kutils version 1.73 Index]