get_complexity_best_optimal_splits {binsegRcpp}

get complexity best optimal splits

Description

Convert output of get_complexity_best_optimal_tree to counts of candidate splits that need to be considered at each iteration.

Usage

get_complexity_best_optimal_splits(node.dt, 
    min.segment.length)

Arguments

node.dt

node.dt

min.segment.length

min.segment.length

Value

Data table with one row for each segment.

Author(s)

Toby Dylan Hocking