compute_duration {admiral} | R Documentation |

Compute duration between two dates, e.g., duration of an adverse event, relative day, age, ...

```
compute_duration(
start_date,
end_date,
in_unit = "days",
out_unit = "days",
floor_in = TRUE,
add_one = TRUE,
trunc_out = FALSE,
type = "duration"
)
```

`start_date` |
The start date A date or date-time object is expected. Refer to Refer to |

`end_date` |
The end date A date or date-time object is expected. Refer to Refer to |

`in_unit` |
Input unit See floor_in and add_one parameter for details. Default: 'days' Permitted Values: 'years', 'months', 'days', 'hours', 'minutes', 'min', 'seconds', 'sec' |

`out_unit` |
Output unit The duration is derived in the specified unit Default: 'days' Permitted Values: 'years', 'months', 'weeks', 'days', 'hours', 'minutes', 'min', 'seconds', 'sec' |

`floor_in` |
Round down input dates? The input dates are round down with respect to the input unit, e.g., if the input unit is 'days', the time of the input dates is ignored. Default: 'TRUE“ Permitted Values: |

`add_one` |
Add one input unit? If the duration is non-negative, one input unit is added. i.e., the duration can not be zero. Default: Permitted Values: |

`trunc_out` |
Return integer part The fractional part of the duration (in output unit) is removed, i.e., the integer part is returned. Default: Permitted Values: |

`type` |
lubridate duration type. See below for details. Default: Permitted Values: |

The output is a numeric vector providing the duration as time from start to end date in the specified unit. If the end date is before the start date, the duration is negative.

The duration between the two date in the specified unit

The lubridate package calculates two types of spans between two dates: duration and interval. While these calculations are largely the same, when the unit of the time period is month or year the result can be slightly different.

The difference arises from the ambiguity in the length of `"1 month"`

or
`"1 year"`

.
Months may have 31, 30, 28, or 29 days, and years are 365 days and 366 during leap years.
Durations and intervals help solve the ambiguity in these measures.

The **interval** between `2000-02-01`

and `2000-03-01`

is `1`

(i.e. one month).
The **duration** between these two dates is `0.95`

, which accounts for the fact
that the year 2000 is a leap year, February has 29 days, and the average month
length is `30.4375`

, i.e. `29 / 30.4375 = 0.95`

.

For additional details, review the lubridate time span reference page.

Date/Time Computation Functions that returns a vector:
`compute_age_years()`

,
`compute_dtf()`

,
`compute_tmf()`

,
`convert_date_to_dtm()`

,
`convert_dtc_to_dtm()`

,
`convert_dtc_to_dt()`

,
`impute_dtc_dtm()`

,
`impute_dtc_dt()`

```
library(lubridate)
# Derive duration in days (integer), i.e., relative day
compute_duration(
start_date = ymd_hms("2020-12-06T15:00:00"),
end_date = ymd_hms("2020-12-24T08:15:00")
)
# Derive duration in days (float)
compute_duration(
start_date = ymd_hms("2020-12-06T15:00:00"),
end_date = ymd_hms("2020-12-24T08:15:00"),
floor_in = FALSE,
add_one = FALSE
)
# Derive age in years
compute_duration(
start_date = ymd("1984-09-06"),
end_date = ymd("2020-02-24"),
trunc_out = TRUE,
out_unit = "years",
add_one = FALSE
)
# Derive duration in hours
compute_duration(
start_date = ymd_hms("2020-12-06T9:00:00"),
end_date = ymd_hms("2020-12-06T13:30:00"),
out_unit = "hours",
floor_in = FALSE,
add_one = FALSE,
)
```

[Package *admiral* version 0.12.1 Index]