| mu.freq {SampleSizeMeans} | R Documentation |
Frequentist sample size determination for normal means
Description
The function mu.freq returns the required sample size
to obtain a confidence interval of given length and confidence level for a normal mean.
Usage
mu.freq(len, lambda, level = 0.95)Arguments
len |
The desired total length of the confidence interval for the mean |
lambda |
Known precision (reciprocal of variance) |
level |
The desired confidence level (e.g., 0.95) |
Details
Assume that a random sample will be collected in order to estimate
the mean of a normally distributed random variable with known precision lambda (precision is the reciprocal of the variance).
The function mu.freq returns the required sample size to attain the
desired length len and confidence level level for a confidence interval
for the mean from a frequentist point of view.
Value
The required sample size given the inputs to the function.
Note
The sample size returned by this function is exact.
Author(s)
Lawrence Joseph lawrence.joseph@mcgill.ca and Patrick Bélisle
References
Lemeshow S, Hosmer Jr DW, Klar J, Lwanga SK.
Adequacy of Sample Size in Health Studies. Wiley and Sons, New York, 1990.
Joseph L, Bélisle P.
Bayesian sample size determination for Normal means and differences between Normal means
The Statistician 1997;46(2):209-226.
See Also
mu.acc, mu.alc, mu.modwoc, mu.varknown, mu.mblacc, mu.mblalc, mu.mblmodwoc, mu.mbl.varknown, mudiff.freq, mudiff.acc, mudiff.alc, mudiff.modwoc, mudiff.acc.equalvar, mudiff.alc.equalvar, mudiff.modwoc.equalvar, mudiff.varknown, mudiff.mblacc, mudiff.mblalc, mudiff.mblmodwoc, mudiff.mblacc.equalvar, mudiff.mblalc.equalvar, mudiff.mblmodwoc.equalvar, mudiff.mbl.varknown
Examples
# Suppose the variance = 4
mu.freq(len=0.2, lambda=1/4)