predict.landmark {Landmarking} | R Documentation |
Predict the risk of an event for a new individual using the landmark model
Description
This function predicts the risk of an event for new data using the landmark model fitted by fit_LME_landmark
or fit_LOCF_landmark
.
The 'event' is defined as event for which event_status
is 1.
Usage
## S3 method for class 'landmark'
predict(object, x_L, x_hor, newdata, cv_fold = NA, ...)
Arguments
object |
Object inheriting the class |
x_L |
Numeric specifying the landmark time. This indicates which landmark model in |
x_hor |
Numeric specifying the horizon time. The function assesses the risk of event before this time. |
newdata |
Data frame containing new data to return the risk prediction of the event of interest. The data should be in in long format
and the columns must contain the covariates and time variables that are used to fit the model.
For the LME model this the variables |
cv_fold |
If cross validation is used to fit |
... |
Arguments passed on to |
Value
Data frame newdata
updated to contained a new column event_prediction
Examples
library(Landmarking)
data(data_repeat_outcomes)
data_model_landmark_LOCF <-
fit_LOCF_landmark(
data_long = data_repeat_outcomes,
x_L = c(60, 61),
x_hor = c(65, 66),
covariates =
c("ethnicity", "smoking", "diabetes", "sbp_stnd", "tchdl_stnd"),
covariates_time =
c(rep("response_time_sbp_stnd", 4), "response_time_tchdl_stnd"),
k = 10,
individual_id = "id",
event_time = "event_time",
event_status = "event_status",
survival_submodel = "cause_specific"
)
newdata <-
rbind(
data.frame(
id = c(3001, 3001, 3001),
response_time_sbp_stnd = c(57, 58, 59),
smoking = c(0, 0, 0),
diabetes = c(0, 0, 0),
ethnicity = c("Indian", "Indian", "Indian"),
sbp_stnd = c(0.45, 0.87, 0.85),
tchdl_stnd = c(-0.7, 0.24, 0.3),
response_time_tchdl_stnd = c(57, 58, 59)
)
)
predict(object=data_model_landmark_LOCF,x_L=60,x_hor=62,newdata=newdata,cv_fold=1)