suitabilityClass {soilassessment} | R Documentation |
A function to determine suitability classes for given indicator values
Description
This function determines the suitability class to which a given indicator value falls based on the crop requirement
Usage
suitabilityClass(value,crop,factor)
Arguments
value |
Input indicator value. |
crop |
The crop of interest for which suitability is determined. |
factor |
The suitability factor for crop requirement. Example factors include: rain, slope, carbonate, EC, ESP, depth, ph, temperature, |
Value
The output is rainfall suitability class for the crop. The output is integer value for suitability class: 1- highly suitable; 2 - moderately suitable; 3 - marginally suitable; 4 - currently not suitable; 5 - not suitable
Note
This function assumes rainfall as the source of water for crop development. The input slope value must be in degrees
Author(s)
Christian Thine Omuto
References
Sys, C., Van Ranst, E., Debaveye, J. and Beerneaert, F.1993. Land evaluation: Part III: Crop requirements. Development Cooperation, Belgium.
Naidu, L.G.K., Ramamurthy, V., Challa O., Hegde, R. and Krishnan, P. 2006. Manual, Soil-site Suitability Criteria for Major Crops, National Bureau of Soil Survey and Land Use Planning, ICAR, Nagpur, India
FAO Crop Suitability Requirements: http://ecocrop.fao.org/ecocrop/srv/en/home
See Also
suitability,slopeSuit, tempSuit
Examples
library(sp)
library(raster)
suitabilityClass(20.14,"saffron","slope")
slope=suitabinput["slope"]
slope$tea=slopeSuit(slope$slope,"tea")
slope$saffron=suitabilityClass(slope$slope,"saffron","slope")
summary(slope$saffron)
spplot(slope["tea"], main="Slope suitability for tea")
spplot(slope["saffron"], main="Slope suitability for saffron")