ratio {nombre}

Convert numbers to ratio character vectors (two to one, one in three, five out of ten)

Description

Convert numbers to ratio character vectors (two to one, one in three, five out of ten)

Usage

ratio(x, sep = "in", max_n = Inf, negative = "negative", ...)

nom_ratio(x, sep = "in", max_n = Inf, negative = "negative", ...)

Arguments

x

A numeric vector

sep

A character vector separating components of the ratio. Defaults to "in".

max_n

A numeric vector. When the absolute value of x is greater than max_n, x remains numeric instead of being converted to words. If max_n is negative, no xs will be converted to words. (This can be useful when max_n is passed by another function.) Defaults to Inf, which converts all xs to words.

negative

A character vector to append to negative numbers. Defaults to "negative".

...

Arguments passed on to fracture::frac_mat

denom

If denom is not NULL, all fractions will have a denominator of denom. This will ignore all other arguments that affect the denominator.

base_10

If TRUE, all denominators will be a power of 10.

common_denom

If TRUE, all fractions will have the same denominator.

If the least common denominator is greater than max_denom, max_denom is used.

max_denom

All denominators will be less than or equal to max_denom.

If base_10 is TRUE, the maximum denominator will be the largest power of 10 less than max_denom.

A max_denom greater than the inverse square root of machine double epsilon will produce a warning because floating point rounding errors can occur when denominators grow too large.

Details

x is converted to a fraction by fracture::frac_mat().

Value

A character vector of the same length as x

See Also

Other number names: adverbial(), cardinal(), collective(), denominator(), numerator(), ordinal()

Examples

paste0("Our team is outnumbered ", nom_ratio(10), ".")
paste0("The chances of winning are ", nom_ratio(1/1000000, sep = "in"), ".")

nom_ratio(c(1, 10, 100))
nom_ratio(c(0, 0.5, 1.5))
nom_ratio(c(0, 0.125, 0.625, 1), sep = "out of", common_denom = TRUE)
nom_ratio(5 / 10, sep = "in", base_10 = TRUE)
nom_ratio(6 / 25, sep = "in")
nom_ratio(6 / 25, sep = "out of", max_denom = 10)