create_colvec_byname {matsbyname}

Create column vectors from data

Description

This function takes data in the .dat and creates column vectors.

Usage

create_colvec_byname(
  .dat,
  dimnames = NA,
  colname = NA,
  matrix_class = c("matrix", "Matrix")
)

Arguments

.dat

Data to be converted to column vectors.

dimnames

The dimension names to be used for creating the column vector, in a list format, or as a data frame column containing a list of the dimension names to be used for each observation.

colname

The name of the column of the colvector.

matrix_class

One of "matrix" or "Matrix". "matrix" creates a base::matrix object with the matrix() function. "Matrix" creates a Matrix::Matrix object using the matsbyname::Matrix() function. This could be a sparse matrix. Default is "matrix".

Details

The row and column names in the resulting column vector are taken from the names of .dat and colname. If set, dimnames overrides the names of .dat and colname.

This function is a "byname" function that can accept a single number, a vector, a list, or a data frame in .dat.

Row types and column types are taken from the row type and column type attributes of .dat.

Value

A column vector, a list of column vectors, or a data frame column of column vectors, depending on the value of .dat and class.

Examples

# Works with single numbers
create_colvec_byname(c(r1 = 1) %>% setrowtype("rt") %>% setcoltype("ct"), 
                     colname = "r1")
# Works with vectors
create_colvec_byname(c(r1 = 1, r2 = 2), colname = "c1")
# Works with a list
create_colvec_byname(list(c(r1 = 1, r2 = 2), c(R1 = 3, R2 = 4, R3 = 5)), 
                     colname = list("c1", "C1"))
# Works in a tibble, too.
# (Must be a tibble, not a data frame, so that names are preserved.)
dat <- list(c(r1 = 1, r2 = 2),
            c(R1 = 2, R2 = 3), 
            c(r1 = 1, r2 = 2, r3 = 3, r4 = 4, r5 = 5, r6 = 6))
cnms <- list("c1", "C1", "c1")
df1 <- tibble::tibble(dat, cnms)
df1
df1 <- df1 %>%
  dplyr::mutate(
    colvec_col = create_colvec_byname(dat, colname = cnms)
  )
df1$colvec_col[[1]]
df1$colvec_col[[2]]
df1$colvec_col[[3]]