do.index {magic}

Apply a function to array element indices

Description

Given a function f() that takes a vector of indices, and an array of arbitrary dimensions, apply f() to the elements of a

Usage

do.index(a, f, ...)

Arguments

a

Array

f

Function that takes a vector argument of the same length as dim(a)

...

Further arguments supplied to f()

Value

Returns a matrix of the same dimensions as a

Note

Tamas Papp suggests the one-liner

function(a, f, ...){array(apply(as.matrix(expand.grid(lapply(dim(a),seq_len),KEEP.OUT.ATTRS=FALSE)),1,f,...),dim(a))}

which is functionally identical to do.index(); but it is no faster than the version implemented in the package, and (IMO) is harder to read.

Further note that function arow() is much much faster than do.index(); it is often possible to rephrase a call to do.index() as a call to arow(); do this where possible unless the additional code opacity outweighs the speed savings.

Author(s)

Robin K. S. Hankin, with improvements by Gabor Grothendieck and Martin Maechler, via the R help list

See Also

arow

Examples

a <- array(0,c(2,3,4))
b <- array(rpois(60,1),c(3,4,5))

f1 <- function(x){sum(x)}
f2 <- function(x){sum((x-1)^2)}
f3 <- function(x){b[t(x)]}
f4 <- function(x){sum(x)%%2}
f5 <- function(x,u){x[u]}

do.index(a,f1)    # should match   arow(a,1)+arow(a,2)+arow(a,3)
do.index(a,f2)
do.index(a,f3)    # same as  apltake(b,dim(a))
do.index(a,f4)    # Male/female toilets at NOC
do.index(a,f5,2)  # same as  arow(a,2)