wafflecut {fancycut}

Like cut, turn a vector of numbers into a factor

Description

Like cut, turn a vector of numbers into a factor

Usage

wafflecut(x, intervals, buckets = intervals, na.bucket = NA,
  unmatched.bucket = NA, out.as.factor = TRUE)

Arguments

x

a numeric vector

intervals

a character vector of intervals

buckets

a character vector of levels for the new factor these have a 1-1 correspondence with intervals

na.bucket

what level should NA values be given?

unmatched.bucket

what level should numbers not covered by an interval be given?

out.as.factor

default is TRUE Should the resulting vector be a factor? If FALSE will return a character vector.

Examples

wafflecut(-10:10, c('[0,2)','[2,5)','[5,10]'), c('Small','Medium','Large'))

wafflecut(-10:10, c('[0,0]','(0,2]','(2,5)','[5,10]'), c('Zero','Small','Medium','Large'))

wafflecut(-10:10, c('[0,2)','[2,5)','[5,10]'), c('Small','Medium','Large'))

wafflecut(-10:10, c('[0,0]','[0,2]','(2,5)','[5,10]'), c('Zero','Small','Medium','Large'))


# The following examples are from Richie Cotton via
# https://www.rdocumentation.org/packages/fancycut/versions/0.1.1/topics/fancycut

# Not all the values have to live in a bucket.
x <- seq.int(0, 1, 0.25)
wafflecut(x, c('(0.2, 0.3)', '(0.7, 0.8)'), c('low', 'high'))

# You can use unmatched.bucket to deal with these other intervals.
x <- seq.int(0, 1, 0.25)
wafflecut(x, c('(0.2, 0.3)', '(0.7, 0.8)'), c('low', 'high'), unmatched.bucket = 'other')

# To match NA values, use na.bucket.
x2 <- c(seq.int(0, 1, 0.25), NA)
wafflecut(x2, c('[0, 0.5)', '[0.5, 1]'), c('low', 'high'), na.bucket = 'missing')