nlsplot {easynls}

Plot nonlinear models

Description

The function plot some nonlinear models

Usage

nlsplot(data, model = 1, start = c(a = 1, b = 1, c = 1, d = 1, e = 1), 
xlab = "Explanatory Variable" , ylab = "Response Variable", position = 1)

Arguments

data

data is a data.frame

The first column should contain the treatments (explanatory variable) and the remaining columns the response variables.

model

define the model

1 = "y~a+b*x" linear

2 = "y~a+b*x+c*x^2" quadratic

3 = "y ~ a + b * (x - c) * (x <= c)" linear plateau

4 = "y ~ (a + b * x + c * I(x^2)) * (x <= -0.5 * b/c) + (a + I(-b^2/(4 * c))) * (x > -0.5 * b/c)" quadratic plateau

5 = "ifelse(x>=d,(a-c*d)+(b+c)*x, a+b*x)" two linear

6 = "y~a*exp(b*x)" exponential

7 = "y~a*(1+b*(exp(-c*x)))^-1" logistic

8 = "y~a*(1-b*(exp(-c*x)))^3" van bertalanffy

9 = "y~a*(1-b*(exp(-c*x)))" brody

10 = "y~a*exp(-b*exp(-c*x)" gompertz

11 = "y~(a*x^b)*exp(-c*x)" lactation curve

12 = "y ~ a + b * (1 - exp(-c * x))" ruminal degradation curve

13 = "y~(a/(1+exp(2-4*c*(x-e))))+(b/(1+exp(2-4*d*(x-e))))" logistic bi-compartmental

start

start iterations values of model

xlab

names of variable x

ylab

names of variable y

position

position of equation in the graph

top=1

bottomright=2

bottom=3

bottomleft=4

left=5

topleft=6 (default)

topright=7

right=8

center=9

Author(s)

Emmanuel Arnhold <[e-mail]>

References

KAPS, M. and LAMBERSON, W. R. Biostatistics for Animal Science: an introductory text. 2nd Edition. CABI Publishing, Wallingford, Oxfordshire, UK, 2009. 504p.

See Also

nlsfit, nls,nls2

Examples

# weights of an Angus cow at ages from 8 to 108 months (Kaps and Lamberson, 2009)

weight=c(280,340,430,480,550,580,590,600,590,600)
age=c(8,12,24,36,48,60,72,84,96,108)

data1=data.frame(age, weight)

# linear
nlsplot(data1, model=1)

# quadratic
nlsplot(data1, model=2)

# linear plateau
nlsplot(data1, model=3)

# quadratic plateau
nlsplot(data1, model=4)

# two linear
nlsplot(data1, model=5, start=c(250,6,2,50))

# exponential
nlsplot(data1, model=6, start=c(250,0.05))

# logistic
nlsplot(data1, model=7, start=c(600,4,0.05))

# van bertalanffy
nlsplot(data1, model=8, start=c(600,2,0.05))

# brody
nlsplot(data1, model=9, start=c(600,4,0.05))

# gompertz
nlsplot(data1, model=10, start=c(600,4,0.05))



# growth of Zagorje turkeys (Kaps and Lamberson, 2009)


weight=c(44,66,100,150,265,370,455,605,770)
age=c(1,7,14,21,28,35,42,49,56)

data2=data.frame(age,weight)

# two linear
nlsplot(data2, model=5, start=c(25,6,10,20))

# using segmented regression to estimate a plateau
# requirement for the methionine will be estimated measurements gain of turkey poults 
#(Kaps and Lamberson, 2009)

methionine=c(80,85,90,95,100,105,110,115,120)
gain=c(102,115,125,133,140,141,142,140,142)

data3=data.frame(methionine, gain)

# linear
nlsplot(data3, model=1)

# quadratic
nlsplot(data3, model=2)

# linear plateau
nlsplot(data3, model=3)

# quadratic plateau
nlsplot(data3, model=4)

# lactation curve
 milk=c(25,24,26,28,30,31,27,26,25,24,23,24,22,21,22,20,21,19,18,17,18,
18,16,17,15,16,14)
 days=c(15,15,15,75,75,75,135,135,135,195,195,195,255,255,255,315,315,
315,375,375,375,435,435,435,495,495,495)
    
 data4=data.frame(days,milk)
	

nlsplot(data4, model=11, start=c(16,0.25,0.004))

# ruminal degradation 
time=c(2,6,9,24,48,72,96)
deg=c(20,33,46,55,66,72,76)

data5=data.frame(time,deg)

nlsplot(data5, model=12)

# logistic bi-compartmental (gas production)
time=c(0,12,24,36,48,60,72,84,96,108,120,144,168,192)
gas=c(0.002,3.8,8,14.5,16,16.5,17,17.4,17.9,18.1,18.8,19,19.2,19.3)
    
data6=data.frame(time,gas)

nlsplot(data6, model=13, start=c(19,4,0.025,0.004,5))