Date-setters {clock}

Setters: date

Description

These are Date methods for the setter generics.

• set_year() sets the year.

• set_month() sets the month of the year. Valid values are in the range of ⁠[1, 12]⁠.

• set_day() sets the day of the month. Valid values are in the range of ⁠[1, 31]⁠.

Usage

## S3 method for class 'Date'
set_year(x, value, ..., invalid = NULL)

## S3 method for class 'Date'
set_month(x, value, ..., invalid = NULL)

## S3 method for class 'Date'
set_day(x, value, ..., invalid = NULL)

Arguments

x

⁠[Date]⁠

A Date vector.

value

⁠[integer / "last"]⁠

The value to set the component to.

For set_day(), this can also be "last" to set the day to the last day of the month.

...

These dots are for future extensions and must be empty.

invalid

⁠[character(1) / NULL]⁠

One of the following invalid date resolution strategies:

• "previous": The previous valid instant in time.

• "previous-day": The previous valid day in time, keeping the time of day.

• "next": The next valid instant in time.

• "next-day": The next valid day in time, keeping the time of day.

• "overflow": Overflow by the number of days that the input is invalid by. Time of day is dropped.

• "overflow-day": Overflow by the number of days that the input is invalid by. Time of day is kept.

• "NA": Replace invalid dates with NA.

• "error": Error on invalid dates.

Using either "previous" or "next" is generally recommended, as these two strategies maintain the relative ordering between elements of the input.

If NULL, defaults to "error".

If getOption("clock.strict") is TRUE, invalid must be supplied and cannot be NULL. This is a convenient way to make production code robust to invalid dates.

Value

x with the component set.

Examples

x <- as.Date("2019-02-01")

# Set the day
set_day(x, 12:14)

# Set to the "last" day of the month
set_day(x, "last")

# You cannot set a Date to an invalid day like you can with
# a year-month-day. Instead, the default strategy is to error.
try(set_day(x, 31))
set_day(as_year_month_day(x), 31)

# You can resolve these issues while setting the day by specifying
# an invalid date resolution strategy with `invalid`
set_day(x, 31, invalid = "previous")