Random values generation from the bivariate Poisson distribution {bivpois}

Random values generation from the bivariate Poisson distribution

Description

Random values generation from the bivariate Poisson distribution.

Usage

rbp(n, lambda)

Arguments

n

The sample size.

lambda

A vector with the three parameters, (\lambda_1,\lambda_2,\lambda_3) of the Poisson distribution.

Details

In order to generate values from this distribution one needs three independent Poisson variables, X_1 \sim \text{Po}\left(\lambda_1\right), X_2 \sim \text{Po}\left(\lambda_2\right) and X_3 \sim \text{Po}\left(\lambda_3\right). Then, \left(X,Y\right)=\left(X_1+X3,X_2+X_3\right) \sim \text{BP}\left(\lambda_1,\lambda_2,\lambda_3\right).

Value

A matrix with n rows and 2 columns.

Author(s)

Michail Tsagris.

R implementation and documentation: Michail Tsagris [e-mail].

References

Kocherlakota S. and Kocherlakota K. (1992). Bivariate discrete distributions. CRC PRess.

See Also

bp.mle

Examples

x <- rbp( 300, c(3, 5, 2) )
bp.mle(x)