sqrt_x {bestNormalize} | R Documentation |
sqrt(x + a) Normalization
Description
Perform a sqrt (x+a) normalization transformation
Usage
sqrt_x(x, a = NULL, standardize = TRUE, ...)
## S3 method for class 'sqrt_x'
predict(object, newdata = NULL, inverse = FALSE, ...)
## S3 method for class 'sqrt_x'
print(x, ...)
Arguments
x |
A vector to normalize with with x |
a |
The constant to add to x (defaults to max(0, -min(x))) |
standardize |
If TRUE, the transformed values are also centered and scaled, such that the transformation attempts a standard normal |
... |
additional arguments |
object |
an object of class 'sqrt_x' |
newdata |
a vector of data to be (potentially reverse) transformed |
inverse |
if TRUE, performs reverse transformation |
Details
sqrt_x
performs a simple square-root transformation in the
context of bestNormalize, such that it creates a transformation that can be
estimated and applied to new data via the predict
function. The
parameter a is essentially estimated by the training set by default
(estimated as the minimum possible), while the base
must be specified beforehand.
Value
A list of class sqrt_x
with elements
x.t |
transformed original data |
x |
original data |
mean |
mean after transformation but prior to standardization |
sd |
sd after transformation but prior to standardization |
n |
number of nonmissing observations |
norm_stat |
Pearson's P / degrees of freedom |
standardize |
was the transformation standardized |
The predict
function returns the numeric value of the transformation
performed on new data, and allows for the inverse transformation as well.
Examples
x <- rgamma(100, 1, 1)
sqrt_x_obj <- sqrt_x(x)
sqrt_x_obj
p <- predict(sqrt_x_obj)
x2 <- predict(sqrt_x_obj, newdata = p, inverse = TRUE)
all.equal(x2, x)