The probability that at the very least one challenge showing 6 is equal to 1 minus probability of constantly getting 5 or below. In various other words, the only means to failure the problem of at least one 6 is to role 5 or listed below for ALL her rolls.

You are watching: Probability of rolling at least one 6

P denotes probability.

P(6) = 1-P(5 or below)

Probability of rolling 5 or below is given by probability of each number multiply by 5 = 1/6 * 5 = 5/6

P(5 or below) = 5/6

We main point 5/6 by itself 3 times together it"s a share probability that 3 rolls.

P(3 roll of 5 or below) = (5/6) * (5/6) * (5/6) = (5/6)^3

Finally calculating probability that at the very least one 6 in 3 rolls:

P(at the very least one 6) = 1-P(3 rolls of 5 or below) = 1 - 0.58 = **0.42**

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