efraction.ml {STAND} | R Documentation |
Calculate ML Estimate of Exceedance Fraction and Confidence Limits
Description
Calculate the ML estimate of the exceedance fraction
and "large sample" confidence limits for lognormal data with non-detects.
Usage
efraction.ml(dd, gam = 0.95, L = 5, dat = TRUE)
Arguments
dd |
if |
gam |
one-sided confidence level |
L |
L is specified limit for the exceedance fraction; e.g., the occupational exposure limit |
dat |
if |
Details
The exceedance fraction FL represent the proportion of the X's that exceed a
given limit Lp. The null hypothesis of interest is ; i.e., Fo is the maximum proportion of the population that can exceed
the limit Lp. The ML point estimate of FL is
where
, and N(v) is the standard normal distribution
function. The large sample
LCL for
is LCLv
, where
,
and p1 and p2 are partial derivatives of with respect to
and
.
The
UCL for FL is
.
The
LCL for FL is
, where
. The null hypothesis
is rejected if the
UCL for FL is less
than Fo, indicating that the exposure profile is acceptable. The large
sample ML estimates of the exceedance fraction and
confidence limits for lognormal data are calculated using the
output from
lnorm.ml
.
Value
A LIST with components:
f |
is the ML estimate of exceedance fraction for lognormal distribution |
f.LCL |
is the 100* |
f.UCL |
is the 100* |
L |
L is specified limit for the exceedance fraction; e.g., the occupational exposure limit |
gam |
one-sided confidence level |
Note
(f.LCL, f.UCL) is an 100 percent confidence interval
for F
Author(s)
E. L. Frome
References
Frome, E. L. and Wambach, P. F. (2005), "Statistical Methods and Software for the Analysis of Occupational Exposure Data with Non-Detectable Values," ORNL/TM-2005/52,Oak Ridge National Laboratory, Oak Ridge, TN 37830. Available at: http://www.csm.ornl.gov/esh/aoed/ORNLTM2005-52.pdf
See Also
Examples
# calculate ML estimate of exceedance fraction and CLs for Example 2 in ORNLTM2005-52
data(beTWA)
unlist(efraction.ml(beTWA,L=0.2))
# calculate nonparametric CLs
unlist(efclnp(beTWA,L=0.2))