MeanCIn {DescTools} | R Documentation |
Returns the required sample size to obtain a given width of a confidence interval for the sample mean. The function uses uniroot()
to find a numeric solution. The t distribution is used.
MeanCIn(ci, sd, interval = c(2, 100000), conf.level = 0.95,
norm = FALSE, tol = .Machine$double.eps^0.5)
ci |
the left and right bound of the interval, which is presumed to be symmetric. |
sd |
the standard deviation of the sample. |
interval |
the interval for the sample size to be searched into, (default is c(2, 100000)). |
conf.level |
confidence level, defaults to |
norm |
logical, determining if the t- or normaldistribution should be used. |
tol |
the desired accuracy (convergence tolerance). |
The required sample sizes for a specific width of confidence interval for the mean depends recursively on the sample size, as the samplesize defines the degrees of freedom in the t-distribution. Although in most practical cases it will be sufficient to use the normal distribution, we might be interested in exact results.
a numeric value
Andri Signorell <andri@signorell.net>
BinomCIn()
MeanCIn(ci=c(25, 27), sd=5)