cricketer {DAAG} | R Documentation |
Lifespans of UK 1st class cricketers born 1840-1960
Description
Year and birth, lifespan, etc, of British first class cricketers, born 1840-1960, whose handedness could be determined from information in the Who's who of cricketers. The status (alive=0, dead =1), and lifetime or lifespan, is for 1992.
Usage
data(cricketer)
Format
A data frame with 5960 observations on the following 8 variables.
left
a factor with levels
right
left
year
numeric, year of birth
life
numeric, lifetime or lifespan to 1992
dead
numeric (0 = alive (censored), 1 = dead, in 1992)
acd
numeric (0 = not accidental or not dead, 1 = accidental death)
kia
numeric (0 = not killed in action, 1 = killed in action)
inbed
numeric (0 = did not die in bed, 1 = died in bed)
cause
a factor with levels
alive
acd
(accidental death)inbed
(died in bed)
Details
Note that those 'killed in action' (mostly during World Wars I and II) form a subset of those who died by accident.
Source
John Aggleton, Martin Bland. Data were collated as described in Aggleton et al.
References
Aggleton JP, Bland JM, Kentridge RW, Neave NJ 1994. Handedness and longevity: an archival study of cricketers. British Medical Journal 309, 1681-1684.
Bailey P, Thorne P, Wynne-Thomas P. 1993. Who's Who of Cricketers. 2nd ed, London, Hamlyn.
Bland M and Altman D. 2005. Do the left-handed die young? Significance 2, 166-170.
See Also
earlycrcktr
.
Examples
data(cricketer)
numLH <- xtabs(~ left+year, data=cricketer)
propLH <- prop.table(numLH, margin=2)[2,]
yr <- as.numeric(colnames(numLH))
plot(propLH ~ yr)
cricketer$lh <- unclass(cricketer$left)-1
left2.hat <- fitted(lm(lh ~ poly(year,2), data=cricketer))
ord <- order(cricketer$year)
lines(left2.hat[ord] ~ cricketer$year[ord])
library(splines)
ns3.hat <- fitted(lm(lh ~ ns(year,3), data=cricketer))
lines(ns3.hat[ord] ~ cricketer$year[ord], col="red")
require(survival)
summary(coxph(Surv(life, kia) ~ bs(year,3) +left, data=cricketer))
cricketer$notacdDead <- with(cricketer, {dead[acd==1]<-0; dead})
summary(coxph(Surv(life, notacdDead) ~ ns(year,2) +left, data=cricketer))