pof_cables_20_10_04kv {CNAIM}  R Documentation 
This function calculates the current annual probability of failure per kilometer for a 20/10/0.4kV cable. The function is a cubic curve that is based on the first three terms of the Taylor series for an exponential function. For more information about the probability of failure function see section 6 on page 30 in CNAIM (2017).
pof_cables_20_10_04kv( hv_lv_cable_type = "1020kV cable, PEX", sub_division = "Aluminium sheath  Aluminium conductor", utilisation_pct = "Default", operating_voltage_pct = "Default", sheath_test = "Default", partial_discharge = "Default", fault_hist = "Default", reliability_factor = "Default", age )
hv_lv_cable_type 
String.
A sting that refers to the specific asset category.
Options:

sub_division 
String. Refers to material the sheath and conductor is
made of. Options:

utilisation_pct 
Numeric. The max percentage of utilisation under normal operating conditions. 
operating_voltage_pct 
Numeric. The ratio in percent of operating/design voltage. 
sheath_test 
String. Only applied for non pressurised cables.
Indicating the state of the sheath. Options:

partial_discharge 
String. Only applied for non pressurised cables.
Indicating the level of partial discharge. Options:

fault_hist 
Numeric. Only applied for non pressurised cables.
The calculated fault rate for the cable in the period per kilometer.
A setting of 
reliability_factor 
Numeric. 
age 
Numeric. The current age in years of the cable. 
Numeric. Current probability of failure per annum for 20/10/0.4kV cables.
DNO Common Network Asset Indices Methodology (CNAIM), Health & Criticality  Version 1.1, 2017: https://www.ofgem.gov.uk/system/files/docs/2017/05/dno_common_network_asset_indices_methodology_v1.1.pdf
# Current annual probability of failure for 1020kV cable, APB, 50 years old pof_cables_10kV_APB < pof_cables_20_10_04kv(hv_lv_cable_type = "1020kV cable, APB", sub_division = "Lead sheath  Copper conductor", utilisation_pct = 80, operating_voltage_pct = 60, sheath_test = "Default", partial_discharge = "Default", fault_hist = "Default", reliability_factor = "Default", age = 50) * 100 paste0(sprintf("Probability of failure %.4f", pof_cables_10kV_APB), " percent per annum")