R: Convert a list of row-vector of equal structure to a...

convertListOfRowsToDataFrame {BBmisc}

R Documentation

Convert a list of row-vector of equal structure to a data.frame.

Description

Elements are arranged in columns according to their name in each element of rows. Variables that are not present in some row-lists, or encoded as NULL, are filled using NAs.

Usage

convertListOfRowsToDataFrame(
  rows,
  strings.as.factors = NULL,
  row.names,
  col.names
)

Arguments

`rows`	[`list`] List of rows. Each row is a list or vector of the same structure, where all corresponding elements must have the same class. It is allowed that in some rows some elements are not present, see above.
`strings.as.factors`	[`logical(1)`] Convert character columns to factors? Default is `default.stringsAsFactors()` for R < "4.1.0" and `FALSE` otherwise.
`row.names`	[`character` \| `integer` \| `NULL`] Row names for result. By default the names of the list `rows` are taken.
`col.names`	[`character` \| `integer`] Column names for result. By default the names of an element of `rows` are taken.

Value

[data.frame].

Examples

convertListOfRowsToDataFrame(list(list(x = 1, y = "a"), list(x = 2, y = "b")))

[Package BBmisc version 1.13 Index]