convertListOfRowsToDataFrame {BBmisc}

Convert a list of row-vector of equal structure to a data.frame.

Description

Elements are arranged in columns according to their name in each element of rows. Variables that are not present in some row-lists, or encoded as NULL, are filled using NAs.

Usage

convertListOfRowsToDataFrame(
  rows,
  strings.as.factors = NULL,
  row.names,
  col.names
)

Arguments

rows

[list]
List of rows. Each row is a list or vector of the same structure, where all corresponding elements must have the same class. It is allowed that in some rows some elements are not present, see above.

strings.as.factors

[logical(1)]
Convert character columns to factors? Default is default.stringsAsFactors() for R < "4.1.0" and FALSE otherwise.

row.names

[character | integer | NULL]
Row names for result. By default the names of the list rows are taken.

col.names

[character | integer]
Column names for result. By default the names of an element of rows are taken.

Value

[data.frame].

Examples

convertListOfRowsToDataFrame(list(list(x = 1, y = "a"), list(x = 2, y = "b")))