WEBVTT
1
00:00:00.440 --> 00:00:02.009 A:middle L:90%
Okay, The first thing we know we could do
2
00:00:02.009 --> 00:00:06.650 A:middle L:90%
for this is evaluate half of negative acts, So
3
00:00:06.650 --> 00:00:09.339 A:middle L:90%
simply plug in negative acts everywhere. Worry you would
4
00:00:09.349 --> 00:00:22.129 A:middle L:90%
otherwise have a positive X. As you can see
5
00:00:22.129 --> 00:00:24.480 A:middle L:90%
, the function is odd from Night of X is
6
00:00:24.480 --> 00:00:27.480 A:middle L:90%
the same thing as negative aftereffects. Therefore, because
7
00:00:27.480 --> 00:00:30.250 A:middle L:90%
we know due to the cemetery, we know that
8
00:00:30.260 --> 00:00:34.990 A:middle L:90%
because it's odd, it's simply gonna be zero as
9
00:00:34.990 --> 00:00:38.170 A:middle L:90%
our solution because we're having the same thing minus the
10
00:00:38.170 --> 00:00:40.390 A:middle L:90%
same thing. So, for example, X minus
11
00:00:40.399 --> 00:00:43.250 A:middle L:90%
X. Therefore, this gives us zero is our
12
00:00:43.250 --> 00:00:45.420 A:middle L:90%
solution for the integral. So this method of cemetery
13
00:00:45.420 --> 00:00:48.119 A:middle L:90%
is a shortcut to figure out the solution to the
14
00:00:48.119 --> A:middle L:90%
integral.